The rate constant for a zero-order reaction is $2 \times 10^{- 2} {mol L}^{- 1} {sec}^{- 1}$ , if the concentration of the reactant after $25 sec$ is $0.25 M$ , calculate the initial concentration.

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Solution

Given: Rate constant $(k) = 2 \times 10^{- 2} {mol L}^{- 1} {sec}^{- 1}$
Concentration at $25 sec$ = $0.25 M$
∴ For zero order reaction, $k = \frac{A_{o} - A}{t}$
$\Rightarrow 2 \times 10^{- 2} = \frac{A_{o} - 0.25}{25}$
$\Rightarrow 2 \times 10^{- 2} = \frac{A_{o}}{25} - \frac{0.25}{25}$
$\Rightarrow 2 \times 10^{- 2} = \frac{A_{o}}{25} - 1 \times 10^{- 2}$

Initial conc. $(A_{o}) = (3 \times 10^{- 2}) \times 25 = 75 \times 10^{- 2} = 0.75 M$

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