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Byju's Answer
Standard XII
Chemistry
Activation Energy
The rate cons...
Question
The rate constant for decomposition of
C
O
C
l
2
(
g
)
according to following reaction
C
O
C
l
2
(
g
)
→
C
O
(
g
)
+
C
l
2
(
g
)
;
Δ
H
=
19
k
c
a
l
/
m
o
l
, expressed as
l
n
k
=
15
−
5000
T
Calculate activation energy for given reaction.
(
i
n
K
c
a
l
/
m
o
l
)
.
Open in App
Solution
l
n
k
=
15
−
5000
T
l
n
k
−
l
n
(
3.27
×
10
6
)
=
−
5000
T
l
n
k
3.27
×
10
6
=
−
5000
T
k
=
3.27
×
10
6
×
e
−
10
/
R
T
Here the activation energy is
10
K
c
a
l
/
m
o
l
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Similar questions
Q.
For the reaction
C
O
(
g
)
+
C
l
2
(
g
)
⇋
C
O
C
l
2
(
g
)
the
K
p
/
K
c
is equal to:
Q.
For the reaction,
C
O
(
g
)
+
C
l
2
(
g
)
⇌
C
O
C
l
2
(
g
)
the
K
p
K
c
is equal to
Q.
For the reaction,
C
O
(
g
)
+
C
l
2
(
g
)
⇌
C
O
C
l
2
(
g
)
, the value of
K
p
/
K
c
is equal to ?
Q.
For the reaction,
C
O
(
g
)
+
C
l
2
(
g
)
⇋
C
O
C
l
2
(
g
)
, the value of
K
p
/
K
c
is equal to:
Q.
C
O
C
l
2
(
g
)
⇌
C
O
(
g
)
+
C
l
2
(
g
)
;
K
1
=
0.329
2
C
O
(
g
)
+
O
2
(
g
)
⇌
2
C
O
2
(
g
)
;
K
2
=
2.24
×
10
22
Calculate the equilibrium constant for the reaction given below from the data given above at
1000
K
:
2
C
O
C
l
2
(
g
)
+
O
2
(
g
)
⇌
2
C
O
2
(
g
)
+
C
l
2
(
g
)
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