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Question

The rate constant for decomposition of COCl2(g) according to following reaction COCl2(g)CO(g)+Cl2(g);ΔH=19kcal/mol, expressed as lnk=155000T
Calculate activation energy for given reaction. (inKcal/mol).

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Solution

ln k=155000T

ln kln(3.27×106)=5000T

lnk3.27×106=5000T

k=3.27×106 ×e10/RT

Here the activation energy is 10 K cal/mol

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