The rate constant for the first-order growth of bacteria can be calculated using:

k = \frac{2.303}{t} {log}_{10} (\frac{a}{a - x})

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k = - \frac{2.303}{t} {log}_{10} (\frac{a}{a + x})

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k = \frac{0.693}{t}

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k = \frac{x}{t}

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Solution

The correct option is B $k = - \frac{2.303}{t} {log}_{10} (\frac{a}{a + x})$

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The rate constant for the first-order growth of bacteria can be calculated using:

The correct option is B k=−2.303tlog10(aa+x)

The correct option is B $k = - \frac{2.303}{t} {log}_{10} (\frac{a}{a + x})$