The rate constant for the hydrolysis reaction of an ester by dilute acid is 0-6931- 10 -3 s -1- The time required to change the concentration of ester from 0-04 M to 0-01 M is-

The correct option is C 2000 sec k=0.06931 s ^ 1 #160;So, t=ln( 0.04 0.01 #160;) #160; #160; 0.06931 =2000 s ^ 1 ...

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Standard XII

Chemistry

Rate Constant

The rate cons...

Question

The rate constant for the hydrolysis reaction of an ester by dilute acid is $0.6931 \times 10^{- 3} s^{- 1}$ . The time required to change the concentration of ester from $0.04$ $M$ to $0.01$ $M$ is:

6931

sec

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4000

sec

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2000

sec

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1000

sec

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Solution

The correct option is C $2000$ sec
$k = 0.06931 s^{- 1}$
So,
$t = \frac{ln (\frac{0.04}{0.01})}{0.06931} = 2000 s^{- 1}$

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The rate constant for the hydrolysis reaction of an ester by dilute acid is 0.6931×10−3 s−1. The time required to change the concentration of ester from 0.04 M to 0.01 M is:

The correct option is C 2000 seck=0.06931s−1 So,t=ln(0.040.01)0.06931=2000s−1

The rate constant for the hydrolysis reaction of an ester by dilute acid is $0.6931 \times 10^{- 3} s^{- 1}$ . The time required to change the concentration of ester from $0.04$ $M$ to $0.01$ $M$ is:

The correct option is C $2000$ sec
$k = 0.06931 s^{- 1}$
So,
$t = \frac{ln (\frac{0.04}{0.01})}{0.06931} = 2000 s^{- 1}$