The rate constant for the reaction2 N 2 O 5- 4 NO 2- O 2is 3-0 - 10-5 sec -1- If the rate is 2-4 - 10-5 mol L -1 sec -1- then the concentration of N 2 O 5 in mole L -1 isA- 1-2B- 0-8C- 0-004D- 1-4

Rate constant (k)=3×10^ 5 sec^ 1 Rate of reaction =2.40×10^ 5 mole L^ 1 sec^ 1 nbsp; Rate of reaction =k× [Molar conc. of N_2O_5] [N_2O_5]=2.40×10^ 53×10^ ...

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Byju's Answer

Standard XII

Chemistry

Rate of Reaction

The rate cons...

Question

The rate constant for the reaction
$2 N_{2} O_{5} \to 4 N O_{2} + O_{2}$
is $3.0 \times 10^{- 5} {sec}^{- 1}$ . If the rate is $2.4 \times 10^{- 5} m o l L^{- 1} {sec}^{- 1}$ , then the concentration of $N_{2} O_{5} (i n m o l e L^{- 1}$ ) is

1.4

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1.2

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0.004

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0.8

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Solution

The correct option is D $0.8$
$Rate constant (k) = 3 \times 10^{- 5} {sec}^{- 1}$
$Rate of reaction = 2.40 \times 10^{- 5} m o l e L^{- 1} {sec}^{- 1}$
$Rate of reaction = k \times [M o l a r c o n c . o f N_{2} O_{5}]$
$[N_{2} O_{5}] = \frac{2.40 \times 10^{- 5}}{3 \times 10^{- 5}} = 0.8 m o l L^{- 1}$

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Similar questions

Q. The rate constant for the reaction

2 N_{2} O_{5} \to 4 N O_{2} + O_{2}

3.0 \times 10^{- 5} {sec}^{- 1}

. If the rate is

2.4 \times 10^{- 5} m o l L^{- 1} {sec}^{- 1}

, then the concentration of

N_{2} O_{5} (i n m o l e L^{- 1}

) is

The rate constant for the first-order reaction, 2 $N_{2}$ $O_{5}$ $\to$ 4 ${N O}_{2}$ + $O_{2}$ is 3.0 $\times$ $10^{- 5}$ $s^{- 1}$ . If the rate is 2.40 $\times$ $10^{- 5}$ $\frac{m o l}{L}$ $s^{- 1}$ , then the initial concentration of $N_{2}$ $O_{5}$ (in $\frac{m o l}{L}$ ) is