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Question

The rate constant for two parallel reactions were found to be 1.0×102dm3 mol1s1 and 3.0×102dm3 mol1s1. If the corresponding energies of activation of the parallel reactions are 60.0 KJ mol1 and 70.0 KJ mol1 respectively, then what is the apparent overall energy of activation?

A
130.0 KJ mol1
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B
65.0 KJ mol1
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C
67.5 KJ mol1
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D
100.0 KJ mol1
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Solution

The correct option is C 67.5 KJ mol1
Overall energy of activation =k1E1+k2E2k1+k2
60×1×102+70×3×1024×102
2704=67.5KJmol1

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