The rate constant k for the reaction 2A-B- product- was found to be 2-5- 10 -5 litre mol -1 sec -1 after 15 sec- 2-60- 10 -5 litre mol -1 sec -1 after 30 sec and 2-55- 10 -5 litre mol -1 sec -1 after 50 sec- The order of the reaction is-

The correct option is A 2 2A+B→ P #160; k=2 5× 10^ 5lt mal^ 1 sec^ 1 unit of k=(mol/lit)^1 order #160; #160; #160; #160; ...

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Standard XII

Chemistry

Order of Reaction

The rate cons...

Question

The rate constant $(k)$ for the reaction $2 A + B \to$ product, was found to be $2.5 \times 10^{- 5}$ litre ${m o l}^{- 1} {s e c}^{- 1}$ after $15$ sec, $2.60 \times 10^{- 5}$ litre ${m o l}^{- 1} {s e c}^{- 1}$ after $30$ sec and $2.55 \times 10^{- 5}$ litre ${m o l}^{- 1} {s e c}^{- 1}$ after $50$ sec.
The order of the reaction is:

2

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Solution

The correct option is A $2$
$2 A + B \to P$
$k = 2 - 5 \times 10^{- 5} l t$ $m a l^{- 1} s e c^{- 1}$
unit of $k = (m o l / l i t)^{1 - o r d e r}$
$1 - o r d e r = - 1$
$\Rightarrow o r d e r = 2$

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Similar questions

Q. The rate constant

(K)

for the reaction,

2 A + B \to

Product was found to be

2.5 \times 10^{- 5}

litre

{m o l}^{- 1} {s e c}^{- 1}

after

15

sec,

2.60 \times 10^{- 5}

litre

{m o l}^{- 1} {s e c}^{- 1}

after

30

sec,

2.55 \times 10^{- 5}

litre

{m o l}^{- 1} {s e c}^{- 1}

after

50

sec.
The order of reaction is:

Q. The rate constant (K) for the reaction,

2 A + B \to

Product was found to be

2.5 \times 10^{- 5}

litre

m o l^{- 1} s e c^{- 1}

after 15 sec,

2.60 \times 10^{- 5} l i t r e m o l^{- 1} s e c^{- 1}

after 30 sec and

2.55 \times 10^{- 5} l i t r e m o l^{- 1} s e c^{- 1}

after 50 sec. The order of reaction is:

Q. The rate constant

(K)

for the reaction

2 A + B \to

product, was found to be

2.5 \times 10^{- 5}

l i t r e m o l^{- 1} s e c^{- 1}

after

15 s e c

2.60 \times 10^{- 5} l i t m o l^{- 1} s e c^{- 1}

after

30 s e c

and

2.55 \times 10^{- 5}

l i t m o l^{- 1} s e c^{- 1}

after

50 s e c

. The order of reaction is:

Q. The rate constant of reaction

2 A + B \to C

2.57 \times 10^{- 5}

l i t r e

{m o l e}^{- 1}

{s e c}^{- 1}

after

10

sec.

2.65 \times 10^{- 5}

l i t r e

{m o l e}^{- 1}

{s e c}^{- 1}

after

20

sec and

2.55 \times 10^{- 5} l i t r e .

{m o l e}^{- 1}

{s e c}^{- 1}

after

30

sec. The order of the reaction is:

Q. The rate constant of the reaction :

2 A + B \to C

2.57 \times 10^{- 5}

l t . m o l^{- 1}

s e c^{- 1}

after 10 sec,

2.65 \times 10^{- 5}

l t . m o l^{- 1} s e c^{- 1}

after 20 sec and

2.55 \times 10^{- 5}

l t . m o l^{- 1} s e c^{- 1}

after 30 sec. The order of the reaction is :

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The rate constant (k) for the reaction 2A+B→ product, was found to be 2.5×10−5 litre mol−1sec−1 after 15 sec, 2.60×10−5 litre mol−1sec−1 after 30 sec and 2.55×10−5 litre mol−1sec−1 after 50 sec. The order of the reaction is:

The correct option is A 22A+B→P k=2−5×10−5lt mal−1sec−1unit of k=(mol/lit)1−order 1−order=−1 ⇒order=2

The correct option is A $2$
$2 A + B \to P$
$k = 2 - 5 \times 10^{- 5} l t$ $m a l^{- 1} s e c^{- 1}$
unit of $k = (m o l / l i t)^{1 - o r d e r}$
$1 - o r d e r = - 1$
$\Rightarrow o r d e r = 2$