Question

The rate constant of a first-order reaction is $0.04307$ minutes${}^{-1}$. What is the half-life of the reaction in days?

• A. $965.6$
• B. $0.01118$
• C. $0.2682$
• D. $16.09$

Answer 1

Answer: (B)

$0.01118$

For first order reaction,

$t_{1/2}=\frac{\ln 2}{K},K\to$ rate constant

$t_{1/2}=\frac{0.693}{0.04307}minutes$

$t_{1/2}=\frac{0.693}{0.04307\times 60\times 24}days$

$t_{1/2}=0.01118days$