The rate constant of a first order reaction is 6.93×10−3min−1. If we start with 10 mol/L, it is reduced to 1.25 mol/L in:
A
100 minutes
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B
200 minutes
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C
30 minutes
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D
300 minutes
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Solution
The correct option is D 300 minutes Given K=6.93×10−3min−1 [A]0=10M,(A)t=1.25M
Hence, for a 1st order reaction we can write t=1Kln[A]0[A]t t=16.93×10−3ln(101.25) ∴t=1036.93×ln8=3×103ln26.93 ⇒t=3×0.693×106.93=3×1031000×693693×100 ∴t=300 minutes