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Question

The rate constant of a reaction at 27oC is 2.3×103min1 and at this temperature 0.001 % of the reactant molecules are able to cross over the energy barrier existing between the reactants and the products. What can the maximum value of rate constant be achieved by raising the temperature?

A
23.0min1
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B
2.3×102min
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C
115.0min1
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D
230.0min1
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Solution

The correct option is D 230.0min1
k=AeEa/RT,
k=2.3×103min1

eEa/RT= Fraction of molecules crossing over energy barrier
=0.001100

=1.0×105

Hence 2.3×103=A×1.0×105;

A=230min1

kmax=A when
T=.

Hence kmax=230min1.

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