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Rate Constant

The rate cons...

Question

The rate constant of a reaction is 110 seconds and 210 seconds at 27C and 37C respectively. Calculate activation energy of the reaction (R = 8.314 JK $m o l^{- 1}$ )

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Solution

$l o g \frac{k_{2}}{k_{1}} = \frac{E_{a}}{2.303 \times R} (\frac{1}{T_{1}} - \frac{1}{T_{2}})$

$l o g \frac{210}{110} = \frac{E_{a}}{2.303 \times 8.314} (\frac{1}{300} - \frac{1}{310})$

$E_{a} = 50 k J {m o l}^{- 1}$

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