1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Chemistry
Arrhenius Equation
The rate cons...
Question
The rate constant of a reaction is
2
×
10
−
2
s
−
1
at
300
K
and
8
×
10
−
2
s
−
1
at
340
K
. Calculate the energy of activation of the reaction.
Open in App
Solution
l
o
g
K
2
K
1
=
E
a
2303
R
[
1
T
1
−
1
T
2
]
l
o
g
8
×
10
−
2
2
×
10
−
2
=
E
a
2303
×
8.314
×
[
1
300
−
1
340
]
11.527
×
300
×
340
40
=
E
a
E
a
=
29.395
K
J
/
m
o
l
Suggest Corrections
1
Similar questions
Q.
The rate constant of a first order reaction at
25
o
C
is
0.24
s
−
1
. If the energy of activation of the reaction is
88
k
J
m
o
l
−
1
, at what temperature would this reaction have rate constant of
4
×
10
−
2
s
−
1
?
Q.
At
400
K
, the rate constant of a chemical reaction is
3
×
10
−
4
s
−
1
and at
300
K
, the rate constant is
6
×
10
−
5
s
−
1
. Find the value of
E
a
i.e. activation energy required for the reaction.
Take:
log
10
(
0.2
)
=
0.7
Q.
For a reaction, the energy of activation is zero. The value of rate constant at 300 K, if k =
1.6
×
10
6
s
−
1
at 280 K is:
Q.
Calculate the rate constant of a reaction at
293
K
when the energy of activation is
103
k
J
m
o
l
−
1
and the rate constant at
273
K
is
7.87
×
10
−
7
s
−
1
.
(
R
=
8.314
×
10
−
3
k
J
m
o
l
−
1
K
−
1
)
Q.
The rate constant of a reaction at
300
K and
310
K is
1.6
×
10
−
3
s
−
1
and
3.2
×
10
−
3
s
−
1
respectively. The activation energy of the reaction (in kcal) is in the range of:
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Arrhenius Equation
CHEMISTRY
Watch in App
Explore more
Arrhenius Equation
Standard XII Chemistry
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app