You visited us 1 times! Enjoying our articles? Unlock Full Access!

Order of Reaction

The rate cons...

Question

The rate constant of $n^{t h}$ order has units:

L i t r e^{- 1} m o l^{1 - n} s e c^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

M o l^{1 - n} l i t r e^{1 - n} s e c^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

M o l^{1 - n} l i t r e^{n - 1} s e c^{- 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

M o l^{1 - n^{2}} l i t r e^{n^{2}} s e c^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $M o l^{1 - n} l i t r e^{n - 1} s e c^{- 1}$
As we know,
For nth order; unit of rate constant may be derived by
$K = \frac{r a t e}{[r e a c t a n t]^{n}}$
$= M o l^{1 - n} l i t r e^{n - 1} s e c^{- 1}$

Suggest Corrections

Similar questions

^{- 1}

^{- 1}

2 A + B \to

2.5 \times 10^{- 5}

m o l^{- 1} s e c^{- 1}

2.60 \times 10^{- 5} l i t r e m o l^{- 1} s e c^{- 1}

2.55 \times 10^{- 5} l i t r e m o l^{- 1} s e c^{- 1}

380^{\circ} C

H_{2} O_{2}

360 m i n

200 k J / m o l^{1}

75

450^{\circ}

[\frac{1}{653} - \frac{1}{723}] = 1.48 \times 10^{- 4}, e^{14.8} = 2.67 \times 10^{6}

K_{b}

m o l^{1}

m o l^{1}

K^{- 1}

Join BYJU'S Learning Program