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Question

The rate constant of the first-order reaction may be described by following equation:


log K = 14.341.25×104T, calculate energy of activation.

A
239.34kJ
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B
239.34 kcal
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C
239.34J
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D
239.34 cal.
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Solution

The correct option is A 239.34kJ
As we know that : lnK=ln AEaRT-------(1)
We have given logK=14.341.25×104T-----(2)

Comparing (1) and (2) we will come to know that Ea2.303R=1.25×104

So Ea=2.303×1.25×104×R
Ea=2.303×1.25×104×8.314
Ea=239.34kJ

Option A is correct.

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