The rate constant of the reaction $A \to B$ is $0.6 \times 10^{- 3} m o l e p e r l i t r e p e r s e c o n d$ . If the concentration of $A$ is $5 M$ , then concentration of $B$ after $20 m i n u t e s$ is:

0.36 M

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0.72 M

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1.08 M

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3.60 M

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Solution

The correct option is C $0.72 M$
The rate constant has unit mole per second which indicates zero order reaction.
x = kt
The concentration of $B$ after 20 minutes is $20 \times 60 \times 0.6 \times 10^{- 3} = 0.72 M$

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Similar questions

A \to B i s 0.6 \times 10^{- 3} m o l L^{- 1} s^{- 1}

A \to B

0.6 \times 10^{- 3} M/s

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The rate constant of the reaction $A \to B$ is $0.6 \times 10^{- 3}$ mole per second. If the concentration of B after 20 min is:

A \to B

0.6 \times 10^{- 3} M/s

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