Question

The rate constant, the activation energy and the Arrhenius parameter of a chemical reaction at ${25}^o$C are $3\times {10}^{-4}$ $se{c}^{-1}$; $104.4$ kJ $mo{l}^{-1}$ and $6.0\times {10}^{14}$ $se{c}^{-1}$ respectively, the value of the rate constant as $T\to \infty$ is:

• A. $2\times {10}^8$ $se{c}^{-1}$
• B. $6\times {10}^{14}$ $se{c}^{-1}$
• C. Infinity
• D. $3.6\times {10}^{30}$ $se{c}^{-1}$

Answer 1

The correct option is B $6\times {10}^{14}$ $se{c}^{-1}$

Arrhenius equation:

$K=A{e}^{-E_a/RT}$

As $T\to \infty ,$

$\frac{-E_a}{RT}\to 0$

$\therefore k\to A$

As $T\to \infty ,$ value of k is equivalent to A.

Given, $A=6\times {10}^{14}se{c}^{-1},k=6\times {10}^{14}se{c}^{-1}.$

Hence, the correct option is $B$