Question

The rate constant, the activation energy and the frequency factor of a chemical reaction at ${25}^{o}C$ are $3.0{10}^{-4}{s}^{-1},104.4KJmo{l}^{-1}$ and $6.0\times {10}^{14}{s}^{-1}$ respectively. The value of the rate constant as $T\to \infty$ is:

• A. $2.0\times {10}^{18}{s}^{-1}$
• B. $6.0\times {10}^{14}{s}^{-1}$
• C. $infinite$
• D. $3.6\times {10}^{30}{s}^{-1}$

Answer 1

Answer: (B)

$6.0\times {10}^{14}{s}^{-1}$

K = A e ${}^{-Ea/RT}$ = A e${}^{\frac{-Ea}{R\times \infty }}$ = A = 6.0 $\times {10}^{14}$ s${}^{-1}$.