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Question

The rate constant, the activation energy and the frequency factor of a chemical reaction at 250C are 3.0×102s1,104.4KJmol1 and 6.0×1014s1, respectively. The value of the rate constant as T is:

A
2.0×1018s1
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B
6.0×1014s1
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C
Infinity
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D
3.6×1030s1
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Solution

The correct option is C 6.0×1014s1
k=A eEa/RT

At T = Infinity, 1T becomes =0. So,

k=A e0

k=A = 6.0×1014 s1



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