The rate constant value for a reaction is 1-75- 10 2 L 2 mol -2 sec -1-The half-life period t 1-2 - -

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Standard XII

Chemistry

Rate Constant

The rate cons...

Question

The rate constant value for a reaction is $1.75 \times 10^{2} L^{2} {m o l}^{- 2} {s e c}^{- 1}$ .The half-life period
$t_{1 / 2} \propto$ ____.

{[R_{0}]}^{- 1}

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{[R_{0}]}^{- 2}

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{[R_{0}]}^{2}

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{[R_{0}]}

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Solution

The correct option is B ${[R_{0}]}^{- 2}$
$L^{2} m o l^{- 1} s e c^{- 1}$ is SI units for third order reaction whose rate law is
$\frac{1}{a^{2}} = \frac{1}{a_{0}^{2}} + 2 k t$

for $a = \frac{a_{0}}{2} :$
$t_{\frac{1}{2}} = \frac{3}{2 k a_{0}^{2}} \Rightarrow t_{\frac{1}{2}} \propto a_{0}^{- 2} (\equiv [R_{0}]^{- 2})$
Option B is correct.

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r = r_{0}

, radial node is formed. Thus for

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\begin{matrix} [A_{0}] & [B_{0}] & R a t e [R_{0}] M o l l i t r e^{- 1} & m o l l i t r e^{- 1} & m o l l i t r e^{- 1} s e c^{- 1} 0.1 & 0.2 & 0.05 0.2 & 0.2 & 0.10 0.1 & 0.1 & 0.05 \end{matrix}

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The rate constant value for a reaction is 1.75×102 L2 mol−2sec−1.The half-life period t1/2∝ ____.

The correct option is B [R0]−2L2mol−1sec−1 is SI units for third order reaction whose rate law is1a2=1a20+2ktfora=a02:t12=32ka20⇒t12∝a−20(≡[R0]−2)Option B is correct.

The rate constant value for a reaction is $1.75 \times 10^{2} L^{2} {m o l}^{- 2} {s e c}^{- 1}$ .The half-life period
$t_{1 / 2} \propto$ ____.