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Question
The rate constants for forward and backward reactions of hydrolysis of ethyl acetate are 1.1×10−2 and1.5×10−3min−1 respectively. The equilibrium constant for the reaction is
The rate constants for forward and backward reactions of hydrolysis of ethyl acetate are 1.1×10−2 and1.5×10−3min−1 respectively. The equilibrium constant for the reaction is
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Solution
The correct option is A 7.33
K=1.1×10−21.5×10−3=7.33
K=1.1×10−21.5×10−3=7.33
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