You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VII

Chemistry

Order of Reaction

The rate law ...

Question

The rate law expression for four reactions are give below. In which case, the percentage increase in the rate of reaction would be maximum when the concentration of A is doubled?

r = k [A]

No worries! We‘ve got your back. Try BYJU‘S free classes today!

r = k [A]^{\frac{3}{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

r = k [A]^{\circ}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

r = k [A]^{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $r = k [A]^{2}$
Larger the order of reaction more the percent increase in the rate of reaction for a given increase in concentration.

Suggest Corrections

Similar questions

In a reaction, $A + B \to$ Product, rate is doubled when the concentration of B is doubled and rate increases by a factor of 8 when the concentrations of both the reactants (A and B) are doubled. Rate law for the reaction can be written as :

Q. For the reaction:

A + B \to C + D

, doubling the concentration of both the reactants increases the reaction rate by 8 times and doubling the concentration of only B simply doubles the reaction rate. The rate law is given as:

Q. For a chemical reaction,

m A ⟶ x B

, the rate law is

r = k [A]^{2}

. If the concentration of

A

is doubled, the reaction rate will be :

Q. For a reaction

A + B \to C

, the rate law is written as

r = k [A]^{2} [B]

. Doubling the concentration of both of

A

and

B

increases the rate of reaction by:

Q. In a reaction,

A + B \to C

, the rate expression is

R = k [A] [B]^{2}

. If the concentration of both the reactant is doubled at constant volume, then the rate of the reaction will be:

Join BYJU'S Learning Program

The rate law expression for four reactions are give below. In which case, the percentage increase in the rate of reaction would be maximum when the concentration of A is doubled?

The correct option is D r=k[A]2Larger the order of reaction more the percent increase in the rate of reaction for a given increase in concentration.

The correct option is D $r = k [A]^{2}$
Larger the order of reaction more the percent increase in the rate of reaction for a given increase in concentration.