Question
the rate law for the reaction, 2Cl2O → 2Cl2 + O2 at 200oC is found to be : rate = k[Cl2O]2
(a) How would the rate change if [Cl2O] is reduced to one-third of its original value?
(b) How should the [Cl2O] be changed in order to double the rate?
(c) How would the rate change if [Cl2O] is raised to threefold of its original value?