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Rate of Reaction

The rate law ...

Question

The rate law of the reaction $2 N_{2} O_{5} \to 4 N O_{2} + O_{2}$ is:

A

r = K [N_{2} O_{5}]

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B

r = K [N_{2} O_{5}]^{2}

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C

r = K [N_{2} O_{5}]^{0}

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D

r = K [N O_{2}]^{4} [O_{2}]

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Solution

The correct option is A $r = K [N_{2} O_{5}]$
Decomposition of $N_{2} O_{5}$ is a 1st order reaction.

$r = K [N_{2} O_{5}]$

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Similar questions

Q. The rate of the reaction

2 N_{2} O_{5} \to 4 N O_{2} + O_{2}

can be written in three ways:

\frac{- d [N_{2} O_{5}]}{d t} = k [N_{2} O_{5}]

\frac{d [N O_{2}]}{d t} = k^{'} [N_{2} O_{5}]

\frac{d [O_{2}]}{d t} = k^{''} [N_{2} O_{5}]

The relationship between

k

k^{'}

Q. For the reaction,

2 N_{2} O_{5} \to 4 N O_{2} + O_{2}

, the rate equation can be expressed in two ways

- \frac{d [N_{2} O_{5}]}{d t} = k [N_{2} O_{5}]

+ \frac{d [N O_{2}]}{d t} = k^{'} [N_{2} O_{5}]

k

k^{'}

are related as:

Q. The rate of the reaction

2 N_{2} O_{5} \to 4 N O_{2} + O_{2}

can be written in three ways:

\frac{- d [N_{2} O_{5}]}{d t} = k [N_{2} O_{5}]

\frac{d [N O_{2}]}{d t} = k^{^{'}} [N_{2} O_{5}]

\frac{d [O_{2}]}{d t} = k^{''} [N_{2} O_{5}]

The relationship between

k

k^{^{'}}

k

k^{''}

2 N_{2} O_{5} \to 4 N O_{2} + O_{2}

- \frac{d [N_{2} O_{5}]}{d t} = k_{1} [N_{2} O_{5}]

\frac{d [N O_{2}]}{d t} = k_{2} [N_{2} O_{5}]

\frac{d [O_{2}]}{d t} = k_{3} [N_{2} O_{5}]

What is the relation between

k_{1}, k_{2} a n d k_{3}

Q. For the reaction

2 N_{2} O_{5} \to 4 N O_{2} + O_{2}

- \frac{d [N_{2} O_{5}]}{d t} = k_{1} [N_{2} O_{5}]

\frac{d [N O_{2}]}{d t} = k_{2} [N_{2} O_{5}]

\frac{d [O_{2}]}{d t} = k_{3} [N_{2} O_{5}]

.
What is the relation between

k_{1}, k_{2}

k_{3}

?

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