Question

The rate of a chemical reaction doubles for every $10{}^{\circ }C$ rise of temperature. If the temperature is raised by $50{}^{\circ }C$, the rate of the reaction increase by about

Answer 1

Given,
For every $10{}^{\circ }C$ rise of temperature, the rate is doubled. Thus, the temperature coefficient of the reaction = 2

Let, the initial rate = $r_1$
New rate $r_2=r_1\times 2^{\left(\text{Temperature difference}/10\right)}$

Temperature is increased by $50{}^{\circ }C$
Hence, rate increases by
$r_2=r_1\times 2^{\left(50/10\right)}=2^5{r}_1$
Hence, the rate is increased by 32 times.