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Question

The rate of a gaseous reaction is given by the expression k[A][B]. If the volume of the reaction vessel is suddenly reduced to 1/4th of the initial volume, the reaction rate relating to original rate will be:

A
1/10
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B
1/8
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C
8
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D
16
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Solution

The correct option is C 16
Concentration is number of moles per liter n/V. it is proportional to volume.

Rate of reaction is k[A][B] where [A] and [B] are a concentration of A and B.

When the volume is suddenly reduced to 1/4 times the original, the concentration changes 4 times the original concentration.

The new rate will be k[4A][4B]=16k[A][B] The new rate will be 16 times the original rate.

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