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Byju's Answer
Standard XII
Chemistry
Arrhenius Equation
The rate of a...
Question
The rate of a particular reaction doubles when temperature changes from
27
o
C
to
37
o
C
. Calculate the energy of activation for such reaction.
[
R
=
8.314
J
K
−
1
m
o
l
e
]
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Solution
l
o
g
K
2
K
1
=
E
a
2.303
R
[
1
T
1
−
1
T
2
]
l
o
g
2
K
K
=
E
a
2.303
×
8.314
×
[
1
300
−
1
310
]
0.3010
×
2.303
×
8.314
×
300
×
310
10
=
E
a
E
a
=
53.603
K
J
/
m
o
l
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Similar questions
Q.
The rate of a reaction doubles when its temperature changes from
300
K
to
310
K
. Activation energy of such a reaction will be:
(
R
=
8.314
J
K
−
1
m
o
l
−
1
a
n
d
log
2
=
0.301
)
Q.
The rate of a reaction triples when temperature changes from
20
o
C
to
50
o
C
. Calculate energy of activation for the reaction.
(
R
=
8.314
J
K
−
1
m
o
l
−
1
)
Q.
The rate of a reaction doubles when its temperature changes from 300 K to 310 K. Activation energy of such a reaction will be:
(
R
=
8.314
J
K
−
1
m
o
l
−
1
and
l
o
g
10
2
=
0.301
)
Q.
The rate of a particular reaction doubles when temperature change from
27
0
C to
37
0
C. Calculate the energy of the activation of such reaction.
Q.
a) The rate of a particular reaction doubles when the temperature changes from 300 K to 310 K. Calculate the energy of activation of the reaction.
[Given :
R
=
8.314
J
K
−
1
m
o
l
−
1
].
b) Show that the half-life period of a first order reaction is independent of initial concentration of reacting species.
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