The rate of a reaction between A and B increases by a factor of 1000 times when the concentration of A is changed from 0.1 mole litre−1 to 1 mole litre −1. The order of the reaction with respect of A is:
A
2
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B
1
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C
3
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D
4
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Solution
The correct option is C 3 rate=k[A]m r→1000r for 0.1 [A] →1[A] i.e.[A]→10[A] so rate 1000=(10)m m = 3