Question

The rate of a reaction is doubled for every ${10}^o$ rise in temperature. The increase in reaction rate as a result of temperature rise form ${10}^{o}Cto{100}^{o}C$ is

• A. 112
• B. 512
• C. 400
• D. 614

Answer 1

The correct option is B 512

$\frac{k_t}{K_1}=\frac{r_t+10}{r_t}=2$

For an increase of temperature of $(100-10=){90}^{o}C$ i.e. $9$ times, the rate of the reaction increases by $2^9$ times i.e. $512.$
Option B is correct.