The rate of change in concentration of C in the reaction 2A-B- 2C-3D was reported as 1 mole litre-1-1- Calculate the reaction rate-

The correct option is D 0.5 mol litre^ 1 sec^ 1 As we know, r = 1/2 d[C ]/d t = 1/2×1 = 0.5 mol litre^ 1 sec^ 1 ...

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Factors Affecting the Rate of a Chemical Reaction

The rate of c...

Question

The rate of change in concentration of C in the reaction $2 A + B \to 2 C + 3 D$ was reported as $1 m o l e l i t r e^{- 1} {sec}^{- 1}$ . Calculate the reaction rate?

0.05 m o l l i t r e^{- 1} s e c^{- 1}

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0.01 m o l l i t r e^{- 1} s e c^{- 1}

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0.5 m o l l i t r e^{- 1} s e c^{- 1}

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Similar questions

2 A + B \to 2 C + 3 D

1.0 m o l l i t r e^{- 1} s e c^{- 1} .

A \to P r o d u c t s

7.5 \times 10^{- 4} m o l l i t r e^{- 1} s e c^{- 1}

A

0.5 m o l l i t r e^{- 1}

(K)

2 A + B \to

2.5 \times 10^{- 5}

l i t r e m o l^{- 1} s e c^{- 1}

15 s e c

2.60 \times 10^{- 5} l i t m o l^{- 1} s e c^{- 1}

30 s e c

2.55 \times 10^{- 5}

l i t m o l^{- 1} s e c^{- 1}

50 s e c

2 A + B \to

2.5 \times 10^{- 5}

m o l^{- 1} s e c^{- 1}

2.60 \times 10^{- 5} l i t r e m o l^{- 1} s e c^{- 1}

2.55 \times 10^{- 5} l i t r e m o l^{- 1} s e c^{- 1}

2 A + B \to C

2.57 \times 10^{- 5}

l t . m o l^{- 1}

s e c^{- 1}

2.65 \times 10^{- 5}

l t . m o l^{- 1} s e c^{- 1}

2.55 \times 10^{- 5}

l t . m o l^{- 1} s e c^{- 1}

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