The rate of change in concentration of C in the reaction 2A-B- 2C-3D was reported as 1-0 mol litre-1 sec-1- Calculate the reaction rate-

The correct option is C 0.5 mol litre^ 1 sec^ 1 r = 1/2 d[C ]/d t = 1/2×1 = 0.5 mol litre^ 1 sec^ 1 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Elementary and Complex Reactions

The rate of c...

Question

The rate of change in concentration of C in the reaction $2 A + B \to 2 C + 3 D$ was reported as $1.0 m o l l i t r e^{- 1} s e c^{- 1} .$ Calculate the reaction rate.

0.05 m o l l i t r e^{- 1} s e c^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.01 m o l l i t r e^{- 1} s e c^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.5 m o l l i t r e^{- 1} s e c^{- 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

5 m o l l i t r e^{- 1} s e c^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

(K)

2 A + B \to

2.5 \times 10^{- 5}

l i t r e m o l^{- 1} s e c^{- 1}

15 s e c

2.60 \times 10^{- 5} l i t m o l^{- 1} s e c^{- 1}

30 s e c

2.55 \times 10^{- 5}

l i t m o l^{- 1} s e c^{- 1}

50 s e c

A \to P r o d u c t s

7.5 \times 10^{- 4} m o l l i t r e^{- 1} s e c^{- 1}

A

0.5 m o l l i t r e^{- 1}

2 A + B \to

2.5 \times 10^{- 5}

m o l^{- 1} s e c^{- 1}

2.60 \times 10^{- 5} l i t r e m o l^{- 1} s e c^{- 1}

2.55 \times 10^{- 5} l i t r e m o l^{- 1} s e c^{- 1}

2 A + B \to 2 C + 3 D

1 m o l e l i t r e^{- 1} {sec}^{- 1}

2 A + B \to C

2.57 \times 10^{- 5}

l t . m o l^{- 1}

s e c^{- 1}

2.65 \times 10^{- 5}

l t . m o l^{- 1} s e c^{- 1}

2.55 \times 10^{- 5}

l t . m o l^{- 1} s e c^{- 1}

Join BYJU'S Learning Program