Question

The rate of diffusion of $2$ gases '$A$' and '$B$' are in the ratio $16:3$. If the ratio of their masses present in the mixture is $2:3$. Then:

• A. the ratio of their molar masses is $16:1$
• B. the ratio of their molar masses is $1:4$
• C. the ratio of their molar present inside the container is $1:24$
• D. the ratio of their moles present inside the container is $8:3$

Answer 1

Answer: (B)

the ratio of their molar masses is $1:4$

We know from Grahams law of effusion,

$\frac{r_1}{r_2}=\frac{\sqrt{M_2}}{\sqrt{M_1}}$

$⟹\frac{16}{3}=\frac{M_2}{M_1}=(64{)}^{\frac{1}{3}}$

$⟹\frac{M_1}{M_2}=1:4$

Hence, option $B$ is correct answer.