Let rate of diffusion of gas z, r1 = a
Therefore, rate of diffusion of methane,r2 = 2 a
According to Graham's Law of Diffusion
r1/r2=√M2/M1
M1 = Molecular mass of gas z
M2 = Molecular mass of Methane = 16 g
Therefore,a/2a= √16/M2
Squaring both the sides,
1/4=16/M2
or, M2 = 16×4=64 g
Hence, the correct answer is 64 g