Question

The rate of diffusion of ozonized oxygen is $0.4\sqrt{5}$ times that of pure oxygen. What is the percent degree of association of oxygen assuming that only pure $O_2$ is present in the sample initially?

• A. $20$
• B. $40$
• C. $60$
• D. none of these

Answer 1

The correct option is C $60$

We knnow,
$\frac{r_{\text{mix}}}{r_{O_2}}=\sqrt{\frac{32}{M_{\text{mix}}}}$
$\Rightarrow M_{\text{mix}}=40g/mol$

Again, $O_2\rightleftharpoons \frac{2}{3}{O}_3$
$\text{initial moles}10$
$\text{at equilibrium}1-\alpha \frac{2}{3}\alpha$
$\therefore \frac{32}{40}=\frac{1-\alpha +\frac{2}{3}\alpha }{1}$
$\Rightarrow \alpha =0.6$
$\therefore$ the required percent of degree of association is $60\%$.