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Question

The rate of emission of a black body at 00C is R. Its rate of emission at 2730C is

A
4R
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B
8R
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C
16R
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D
32R
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Solution

The correct option is C 16R
For rate of emission of black body, ϕT4
At 0oC i.e. 273K;ϕ=R
At 273oC i.e. 546K;ϕ=?

ϕ1ϕ2=T14T24Rϕ2=(273)4(2×273)4=(273)4(273)4×24ϕ2=24R=16R
Required rate of emission at 273oC is 16R.

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