Question

The rate of emission of a black body at temperature $27$${}^o$C is $E_1$. If its temperature is increased to $327$${}^o$C, the rate of emission of radiation is $E_2$. The relation between $E_1$ and $E_2$ is :

• A. $E_2=24E_1$
• B. $E_2=16E_1$
• C. $E_2=8E_1$
• D. $E_2=4E_1$

Answer 1

The correct option is B $E_2=16E_1$

We know the relation for emissive power of body: $\frac{E_1}{E_2}=\frac{T_1^4}{T_2^4}$
$T_1=27+273=300K$
$T_2=327+273=600K$
So, putting all these data in above formulas, we get
$E_2=16E_1$