The rate of first order reaction- A - Products is 7-5 - 10-4 mol litre-1 sec-1- If the concentration of A is 0-5 mol litre-1- the rate constant is-

The correct option is D 1.5 × 10^ 3 sec^ 1 Rate =k[A].(given) 7.5× 10 ^ 4 =k[0.5] k=7.5× 2× 10 ^ 4 sec ^ 1 k=1.5× 10 ^ 3 sec ^ ...

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Standard XII

Chemistry

Rate Constant

The rate of f...

Question

The rate of first order reaction, $A \to P r o d u c t s$ is $7.5 \times 10^{- 4} m o l l i t r e^{- 1} s e c^{- 1}$ . If the concentration of $A$ is $0.5 m o l l i t r e^{- 1}$ , the rate constant is:

3.75 \times 10^{- 4} s e c^{- 1}

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2.5 \times 10^{- 5} s e c^{- 1}

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1.5 \times 10^{- 3} s e c^{- 1}

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8.0 \times 10^{- 4} s e c^{- 1}

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Solution

The correct option is D $1.5 \times 10^{- 3} s e c^{- 1}$
Rate $= k [A] . (g i v e n) 7.5 \times 10^{- 4} = k [0.5] k = 7.5 \times 2 \times 10^{- 4} {s e c}^{- 1} k = 1.5 \times 10^{- 3} {s e c}^{- 1}$

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Similar questions

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The rate of first order reaction, A→ Products is 7.5×10−4 mol litre−1sec−1. If the concentration of A is 0.5 mol litre−1, the rate constant is:

The correct option is D 1.5×10−3sec−1Rate=k[A].(given)7.5×10−4=k[0.5]k=7.5×2×10−4sec−1k=1.5×10−3sec−1

The rate of first order reaction, $A \to P r o d u c t s$ is $7.5 \times 10^{- 4} m o l l i t r e^{- 1} s e c^{- 1}$ . If the concentration of $A$ is $0.5 m o l l i t r e^{- 1}$ , the rate constant is:

The correct option is D $1.5 \times 10^{- 3} s e c^{- 1}$
Rate $= k [A] . (g i v e n) 7.5 \times 10^{- 4} = k [0.5] k = 7.5 \times 2 \times 10^{- 4} {s e c}^{- 1} k = 1.5 \times 10^{- 3} {s e c}^{- 1}$