Question

The rate of formation of a dimer in a second order dimerisation reaction is $9.1\times {10}^{-6}mol{L}^{-1}{s}^{-1}$ at $0.01mol{L}^{-1}$ monomer concentration. What will be the rate constant for the reaction?

• A. $9.1\times {10}^{-2}Lmo{l}^{-1}{s}^{-1}$
• B. $9.1\times {10}^{-6}Lmo{l}^{-1}{s}^{-1}$
• C. $3\times {10}^{-4}Lmo{l}^{-1}{s}^{-1}$
• D. $27.3\times {10}^{-2}Lmo{l}^{-1}{s}^{-1}$

Answer 1

The correct option is A $9.1\times {10}^{-2}Lmo{l}^{-1}{s}^{-1}$

$2A\to A_2$

Rate of formation of dimer $=k[A{]}^2$

$k=\frac{\text{Rate of formation of dimer}}{[A{]}^2}$

$k=\frac{9.1\times {10}^{-6}mol{L}^{-1}{s}^{-1}}{(0.01mol{L}^{-1}{)}^2}=9.1\times {10}^{-2}Lmo{l}^{-1}{s}^{-1}$.