Question

The rate of a chemical reaction doubles for every $10°\mathrm{C}$ rise in temperature. If the temperature is raised by $50°\mathrm{C}$,The rate of the reaction increases by about?

Answer 1

Step 1: Given information:

• For every $10°\mathrm{C}$ increase in temperature, a chemical reaction's rate doubles.

Step 2: Calculate the rate of the reaction when the temperature is raised by $50°\mathrm{C}$

• The pace of a chemical reaction doubled for every $10°\mathrm{C}$ increase in temperature.
• When the temperature is raised by $50°\mathrm{C}$.
• The rate of reaction can be expressed as:

$$\begin{gathered} \frac{\mathrm{Rate}\mathrm{at}{50}^{°}\mathrm{C}}{\mathrm{Rate}\mathrm{at}{{\mathrm{T}}_1}^{°}\mathrm{C}}={\left(2\right)}^{\frac{△\mathrm{T}}{{\mathrm{T}}_1}} \\ ={\left(2\right)}^{\frac{50}{10}} \\ =2^5 \\ =32 \end{gathered}$$

Therefore, the rate of the reaction increases by $32$ times.