The rate of the reaction, 2NO+O2⟶2NO2, at 25oC is 0.028molL−1s−1. The experimental rate is given by, r=k[NO]2[O2]. If the initial concentrations of the reactants are O2=0.040molL−1 and NO=0.01molL−1, the rate constant of the reaction is:
A
7.0×10−2Lmol−1s−1
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B
7.0×10−4L2mol−2s−1
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C
7.0×102L2mol−2s−1
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D
7.0×103L2mol−2s−1
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Solution
The correct option is D7.0×103L2mol−2s−1 r=k[NO]2[O2] Now, using given quantities: 0.028=k.(0.04)(0.01)k=7×10−3L2mol−2s−1