Question

The rate of the reaction, $3A+2B⟶$ Products, is given by the rate expression:
Rate $=k\left[A\right]{\left[B\right]}^2$
If $A$ is taken in excess, the order of the reaction would be:

• A. $3$
• B. $2$
• C. $1$
• D. $5$

Answer 1

The correct option is B $2$

When $A$ is taken in excess, its concentration will become constant; the rate law may, therefore, be given as:
Rate $=k^{{}^{\prime }}{\left[B\right]}^2$
Order $=2$