Question

The rate of the reaction $A\to$ Products, at the initial concentration of $3.24\times {10}^{-2}M$ is $9$ times its rate at another initial concentration of $1.2\times {10}^{-3}M$. The order of the reaction is:

Answer 1

$\frac{r_1}{r_2}$ = $(\frac{\left[A_0\right]}{\left[A_1\right]}{)}^n$

$\frac{9}{1}=(\frac{3.24\times {10}^{-2}}{1.2\times {10}^{-3}}{)}^n$

$9={\left(27\right)}^n$

$n=\frac{2}{3}$