The rate of the reaction
$C H_{3} C O O C_{2} H_{5} + N a O H \to C H_{3} C O O N a + C_{2} H_{5} O H$ is given as rate= $K [C H_{3} C O O C_{2} H_{5}] {[N a O H]}_{+}$ .If three times water is added to the reaction mixture,what will be the rate of the reaction compared to the original rate?

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Solution

There would be no change in the rate when Water is added three times to the reaction mixture.
Since the rate doesn't depend on the concentration of water.
$R a t e = K [C H_{3} C O O C_{2} H_{5}] [N a O H]$

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Similar questions

C H_{3} C O O C_{2} H_{5} + N a O H \to C H_{3} C O O N a + C_{2} H_{5} O H

= K [C H_{3} C O O C_{2} H_{5}] [N a O H]

C H_{3} C O O C_{2} H_{5} + H_{2} O H^{+} - ----- \to C H_{3} C O O H + C_{2} H_{5} O H

C H_{3} C O O C_{2} H_{5} + H_{2} O ⇌ C H_{3} C O O H + C_{2} H_{5} O H

2

2

(C H_{3} C O)_{2} O A + C_{2} H_{5} O H B ⟶ {C H}_{3} C O O C_{2} H_{5} + {C H}_{3} C O O H

k [A] [B]

k [A]

{C H}_{3} C O O H

C_{2} H_{5} O H

\frac{2}{3}

{C H}_{3} C O O C_{2} H_{5}

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