1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# The ratio between kinetic and potential energies of a body executing simple harmonic motion, when it is at a distance of 1N of its amplitude from the mean position is

A
N2+1
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
B
1N2
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
C
N2
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
D
N21
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

## The correct option is D N2−1Let the amplitude of oscillation of SHM be AThus the distance of body from mean position x=ANKinetic energy K.E=12mω2(A2−x2)∴ K.E=12mω2(A2−A2N2)=12mω2A2(N2−1N2) ..........(1)Potential energy P.E=12kx2 where k=mω2∴ P.E=12mω2A2N2 .........(2)⟹ K.EP.E=N2−1N21N2=N2−1

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Expression for SHM
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program