Question

The ratio between peak hourly water demand and maximum daily demand (per hour of course) is:

• A. 1.8
• B. 2.0
• C. 1.5
• D. 2.7

Answer 1

The correct option is C 1.5

Max. hourly demand of max. day
= 1.5 (Average hourly demand of max. day)

$=1.5\left(\frac{\text{Max. daily demand}}{24}\right)$

Note:
(i) Maximum daily consumption$=1.8\times \text{Average daily demand}$
(ii) Maximum hourly consumption $=1.5\times \text{Average hourly consumption of maximum day}$

$=1.5\times \left(\frac{\text{Maximum daily demand}}{24}\right)$

$=1.5\times 1.8\times \left(\frac{\text{Average daily demand}}{24}\right)$

$=2.7\times \left(\text{Annual average hourly demand}\right)$