Question

The ratio between the number of neutrons present in ${}^{12}C$ and ${}^{30}Si$ atoms is:

• A. $3:8$
• B. $2:5$
• C. $3:7$
• D. $1:1$

Answer 1

The correct option is A $3:8$

${}^{12}C$ has $6$ protons and $6$ neutrons.

${}^{30}Si$ has $16$ neutrons and $14$ protons.

Hence, the ratio between the number of neutrons is $6:16$, i.e., $3:8$.

Note: The number of neutrons is the difference between mass number and atomic number.