The ratio between the speeds of two airplanes is 11: 13. If the second plane runs 2600 kms in 5 hours, then the speed of the first plane is:

375 km/hr

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440 km/hr

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480 km/hr

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360 km/hr

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450 km/hr

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Solution

The correct option is B
440 km/hr

Let the speed of two planes be 11x and 13x kmph.

Then, 13x = $\frac{2600}{5} = 520$ kmph

x = $\frac{520}{13}$ = 40 kmph

Therefore, speed of first plane = (11 $\times$ 40) kmph = 440 kmph

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The ratio between the speeds of two airplanes is 11: 13. If the second plane runs 2600 kms in 5 hours, then the speed of the first plane is:

The correct option is B 440 km/hr Let the speed of two planes be 11x and 13x kmph. Then, 13x = 26005=520 kmph x =52013 = 40 kmph Therefore, speed of first plane = (11 × 40) kmph = 440 kmph

The correct option is B
440 km/hr

Let the speed of two planes be 11x and 13x kmph.

Then, 13x = $\frac{2600}{5} = 520$ kmph

x = $\frac{520}{13}$ = 40 kmph

Therefore, speed of first plane = (11 $\times$ 40) kmph = 440 kmph