wiz-icon
MyQuestionIcon
MyQuestionIcon
3
You visited us 3 times! Enjoying our articles? Unlock Full Access!
Question

The ratio by which the line 2x+5y−7=0 divides the straight line joining the points (−4,7) and (6,−5) is

A
1:4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1:2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1:1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
2:3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
1:3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D 1:1
Using the section formula, if a point (x,y) divides the line joining the points (x1,y1) and (x2,y2) in the ratio m:n, then (x,y)=(mx2+nx1m+n,my2+ny1m+n)

Let the line 2x+5y7=0 divide the straight line joining points (4,7) and (6,5) in the ratio m:n, then the point of intersection by Section Formula is (4m+6nm+n,7m5nm+n)

Since the intersection point lies on the given line, we have 2×(4m+6nm+n)+5×(7m5nm+n)7=0

8m+12n+35m25n7m7n=0

20m=20n

m:n=1:1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Section Formula
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon