Question

The ratio (in $S$$I$ units) of magnetic dipole moment to that of the angular momentum of an electron of mass ${}^{\prime }m{}^{\prime }$kg and charge $e$ coulomb in Bohr's orbit of hydrogen atom is

• A. $\frac{e}{2m}$
• B. $\frac{e}{m}$
• C. $\frac{2e}{m}$
• D. None of these

Answer 1

The correct option is A $\frac{e}{2m}$

Magnetic dipole moment: $\mu =\frac{e}{2m}L$
where, $L$ is the angular momentum