The ratio in which the line joining (2, 4, 5) and (3, 5, -9) is divided by the
yz-plane is
Let A = (2, 4, 5) and B = (3, 5, -9)
Let the line joining A and B be divided by the
yz-plane at point P in the ratio λ: 1
Then, we have
P = (3λ+2λ+1,5λ+4λ+1,−9λ+5λ+1)
Since P lies on the yz-plane, the x-coordinate of P will be zero.
∴3λ+2λ+1=0
⇒3λ+2=0
⇒λ=−23
Hence, the yz-plane divides AB in the ratio - 2 : 3