The ratio in which the line joining $(2, - 4, 3) a n d (- 4, 5, - 6)$ is divided by the plane $3 x + 2 y + z - 4 = 0$ is

2:1

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4:3

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-1:4

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2:3

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Solution

The correct option is C
-1:4

$\frac{- (a x_{1} + b y_{1} + c z_{1} + d)}{(a x_{2} + b y_{2} + C z_{2} + d)} = - 1 : 4$

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Similar questions

The ratio in which the line joining $(2, - 4, 3) a n d (- 4, 5, - 6)$ is divided by the plane $3 x + 2 y + z - 4 = 0$ is

3 x + 2 y = 2

(- 6, - 2)

(4, 3)

(2, - 4, 3), (- 4, 5, - 6)

(i) 1 : - 4

(i i) 2 : 1

A (2, 1, 5)

B (3, 4, 3)

x + 2 y - z = 0

3 x + 2 y = 2

(- 6, - 2)

(4, 3)

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